A pilot and a flight attendant get married and leave for their honeymoon on an airplane. Well-meaning friends pack the plane with balloons. As the plane gains altitude, the balloons begin to pop. -Using the ideal gas law, explain why the balloons popped. -One balloon was only partly filled when put on the plane. During the flight, the balloon volume increased from 7 L at 1.0 atm to 9 L. What was the cabin pressure on the airplane during the flight? (Assume the balloon stretched very easily and the temperature was

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smecloudbird18 smecloudbird18 · Answer 1 · 2022-07-13T09:22:32+02:00

The balloons popped because

As plane rise, the pressure in the cabin is decreases at constant temperature. According to Boyle's law the pressure is inversely proportional to the volume. Therefore, as pressure decreases then volume increases and cause balloon to pop.

The expression of Boyle's law is given as,

P ∝ 1/V

P = K/V

Calculation,

Let P1 = Initial pressure = 1 atm

P2 = Final pressure = ?

V1 = Initial volume - 7 L

V2 = Final volume = 9 L

Then two Boyle's law expression are,

P1 = K/V1

K = P1V1 ...(i)

And, P2 = K/V2

K = P2V2 ...(ii)

Comparing equation i and ii we get,

P1V1 = P2V2

Putting the values of P1, V1 and V2 from question in above equation then we get the value of P2,

7 L×1 atm = P2×9 L

P2 = 0.77 atm

So, the cabin's pressure is 0.77 atm.

learn about Boyle's law,

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