gvldjayy gvldjayy

26-04-2017
Chemistry

contestada

how much 6.0M HNO(small 3) is needed to neutralize 39mL of 2 M KOH

how much 60M HNOsmall 3 is needed to neutralize 39mL of 2 M KOH class=

Respuesta :

jstone0050 jstone0050

26-04-2017

Equation of reaction
KOH+HNO3--->KNO3+H2O
CA=6.0M, CB=2.0M, VA=?, VB=39ml, na=1, nb=1
CAVA/CBVB=na/nb
6*VA/2*39=1/1
6VA/78=1
6VA=78
VA=78/6. VA=13ml.
VA=13ml.
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