In the pendulum formula , we use g = 9.8 m/s2 for the acceleration due to gravity on Earth. But what about on the Moon? If an astronaut on the surface of the moon swings a 1-meter long pendulum, and it has a period of 4.9 seconds, what is the acceleration due to gravity, g, on the moon?

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1.6 m/s^2 

Answer:

The acceleration due to gravity on the moon is 1.642 m/s².      

Step-by-step explanation:

Given : In the pendulum formula , we use g = 9.8 m/s2 for the acceleration due to gravity on Earth. If an astronaut on the surface of the moon swings a 1-meter long pendulum, and it has a period of 4.9 seconds.

To find : What is the acceleration due to gravity, g, on the moon?        

Solution :

The pendulum formula is [tex]T=2\pi \sqrt{\frac{L}{g}}[/tex]

where, T is the time period,

L is the length of the pendulum,

g is the acceleration due to gravity

We have to find the value of g acceleration due to gravity on the moon.

The formula became,

[tex]g'=(\frac{2\pi}{T})^2\times L[/tex]

Substitute T=4.9 seconds , L= 1 m

[tex]g'=(\frac{2\times 3.14}{4.9})^2\times 1[/tex]

[tex]g'=(\frac{6.28}{4.9})^2[/tex]

[tex]g'=\frac{39.4384}{24.01}[/tex]

[tex]g'=1.642[/tex]

The acceleration due to gravity on the moon is 1.642 m/s².