Answer:
[tex]Q = 150 J[/tex]
Explanation:
Heat required to raise the temperature of the object is given as
[tex]Q = m s \Delta T[/tex]
here we know that
m = mass of the object
m = 25 grams
s = specific heat capacity of the object
[tex]s = 0.39 J/g ^oC[/tex]
[tex]\Delta T[/tex] = temperature change
[tex]\Delta T = 15^o C[/tex]
now we know that
[tex]Q = 25 \times 0.39 \times 15[/tex]
[tex]Q = 150 J[/tex]