What is the value of the discriminant, b2 − 4ac, for the quadratic equation 0 = x2 − 4x + 5, and what does it mean about the number of real solutions the equation has?
in your problem a = 1, b = -4 and c = 5 so discriminant is -4 the discriminat is the value under the radical so if the number is negative there is no real solution. if the number is 0 there is one solution if the number is positive there are two solutions
