This is one of those problems that requires you to translate words into equations.3 consecutive odd integers: let the middle integer be y, then the first one will be y-2, the third one will be y+2.Product of first and third = 6 + 3*(second).(y-2)(y+2) = 6 + 3*yy^2 - 4 = 6 + 3*yy^2 - 3*y - 10 = 0This is a quadratic equation, with two solutions y=5 and y=-2.So your 3 numbers are 3, 5, and 7.-nightmist
