Answer:
It goes to the height of 0.50 m.
Explanation:
Given that,
Initial velocity = 3.1 m/s
We need to calculate the height
Firstly, We calculate the time
Using equation of motion
[tex]v=u+gt[/tex]
[tex]t=\dfrac{v-u}{g}[/tex]
Where, v = final velocity
u = initial velocity
t = time
g = acceleration due to gravity
Put the value in the equation
[tex]t=\dfrac{0-3.1}{-9.8}[/tex]
[tex]t =0.32\ sec[/tex]
Now, We calculate the height
Using equation of motion
[tex]s=ut+\dfrac{1}{2}gt^2[/tex]
Where, s = height
t = time
Put the value in the equation
[tex]s=0+\dfrac{1}{2}\times9.8\times(0.32)^2[/tex]
[tex]s=0.50\ m[/tex]
Hence, It goes to the height of 0.50 m.
