The distance travelled by the airplane, is 432 meters.
Given the following data:
- Initial velocity = 0 m/s (since the airplane starts from rest).
- Acceleration = 6.0 [tex]m/s^2[/tex]
To find the distance travelled by the airplane, we would use the second equation of motion:
Mathematically, the second equation of motion is given by the formula;
[tex]S = ut + \frac{1}{2} at^2[/tex]
Where:
- S is the distance travelled.
- u is the initial velocity.
- t is the time measured in seconds.
Substituting the parameters into the formula, we have;
[tex]S = 0(12) + \frac{1}{2}(6)(12^2)\\\\S = 3(144)[/tex]
[tex]S = 3[/tex] × [tex]144[/tex]
Distance, S = 432 meters.
Therefore, the distance travelled by the airplane, is 432 meters.
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