Answer:
First quartile = 36 , Median = 64 , Minimum = 20 ,
Maximum = 102, Third quartile = 89.
Step-by-step explanation:
Given : 63,98,40,32,20,80,102,65.
To find : What are the minimum,first quartile,median,third quartile,and maximum of the data set.
Solution : We have given that 63,98,40,32,20,80,102,65.
Arranging in ascending order
20 , 32 , 40 ,63 ,65 ,80 ,98 , 102.
Median = [tex]\frac{63 +65}{2} =\frac{128}{2}[/tex] = 64.
Minimum = 20 .
Maximum = 102.
First quartile = [tex]\frac{32 +40}{2} = 36.
Third quartile = [tex]\frac{80 +98}{2} = 89.
Therefore, First quartile = 36 , Median = 64 , Minimum = 20 ,
Maximum = 102, Third quartile = 89.
