Respuesta :

[tex]\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=\textit{angle in degrees}\\ r=radius\\ ---------\\ \theta=45\\ r=8 \end{cases}\implies A=\cfrac{45\cdot \pi \cdot 8^2}{360}[/tex]

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