What is the measure of JHN?
25°
45°
50°
95°

The measure of angle of JHN is [tex]25^0[/tex] .
Angle is formed by two rays lie in the plane that contains the rays.
We have,
[tex]\angle MHL=(3x+20)^{0}[/tex]
[tex]\angle JHN=(x+20)^{0}[/tex]
[tex]\angle NHK=(x+25)^{0}[/tex],
We have,
[tex]\angle MHL[/tex] and [tex]\angleJHK[/tex][tex]\angle JHK[/tex] are vertically opposite angles.
i.e.
[tex]\angle MHL=\angle JHK[/tex]
So,
[tex]\angle MHL=\angle JHN + \angle NHK[/tex]
[tex]3x+20=(x+20)+(x+25)[/tex]
[tex]3x+20=2x+45[/tex]
[tex]x=25^0[/tex]
Hence, we can say that the measure of angle of JHN is [tex]25^0[/tex] .
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