Answer:
[tex]n^{th}[/tex] term of AP = a + (n-1) d
Step-by-step explanation:
Let the first term of arithmetic progression be a and common difference be d.
We have the AP
a , a + d, a+ 2d, a+3d..............................
a + (1-1)d , a + (2-1)d, a + (3-1)d, a + (4-1)d..............................
So if we need [tex]n^{th}[/tex] term, we can find it as
[tex]a_n=a+(n-1)d[/tex]
[tex]n^{th}[/tex] term of AP = a + (n-1) d
