Wavelength is obtained by Planck’s constant over the product of mass and velocity.
w = h / mv
w =wavelength
h = Planck’s constant =
6.626 x 10^-34
m = mass (kg)
= 9.11 x 10^-31
v = velocity =
7.3 x 10^7 m/sec
Substitute all the given to the formula.
w = 6.626 x 10^-34 / (9.11
x 10^-31)(7.3 x 10^7)
w = 0.00996 nm ≈ 1 x 10^-11 m
The answer is A
Answer:
A. [tex]\lambda_{db} = 1.0 \times 10^{-11} m[/tex]
Explanation:
As we know that de Broglie wavelength is given by the formula
[tex]\lambda_{db} = \frac{h}{mv}[/tex]
here we know that
[tex]h = 6.6 \times 10^{-34}[/tex]
mass of electron is given as
[tex]m = 9.1 \times 10^{-34} kg[/tex]
[tex]v = 7.3 \times 10^7 m/s[/tex]
so here we have
[tex]\lambda_{db} = \frac{6.6 \times 10^{-34}}{(9.1 \times 10^{-31})(7.3 \times 10^7)}[/tex]
[tex]\lambda_{db} = 0.99 \times 10^{-11} m[/tex]
[tex]\lambda_{db} = 1.0 \times 10^{-11} m[/tex]
