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if several pea plants with the genotype TTYy are crossed with pea plants with the genotype Ttyy what percentage of the offspring will be expected to have the TTYy allele combination

Respuesta :

Answer: 25%

Explanation:

A cross between two heterozygous plant can will result in the following pair.

To get this combination we need to cross the first pair individually and then the second pair individually.

    T         T                        Y         y

T   TT     TT                   y   Yy     yy

t    Tt       Tt                   y   Yy      yy

The ratio of TT= 1/2        The ratio of Yy= 1/2

The total ratio of TTYy= 1/2* 1/2 = 1/4 which is 25% of the total offspring produced by the cross between the pair TTYy and  Ttyy.

The offspring produced is heterozygous.

mahima6824soni

The percentage of the offspring will be expected to have TTYy allele combination is 25%.

What is punnet square?

The Punnett square is a diagram with squares used to forecast genotypes in a cross or breeding experiment. This square is named after  Reginald C. Punnett, who invented this ides in 1905.

Two heterozygous plant cross will result:

   T         T                        Y         y

T   TT     TT                   y   Yy     yy

t    Tt       Tt                   y   Yy      yy

The ratio of TT=  [tex]\dfrac{1}{2}[/tex]       The ratio of Yy=  [tex]\dfrac{1}{2}[/tex]

The total ratio of TTYy =  [tex]\bold{\dfrac{1}{2}\times \dfrac{1}{2} =\dfrac{1}{4}}[/tex]  is 25% of the total offspring produced by the cross between the pair TTYy and  Ttyy.

Thus, The offspring produced is heterozygous.

Learn more about genotype, here:

https://brainly.com/question/20730322

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