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Stu wanted to calculate the resistance of a light bulb connected to a 4.0-V battery, with a resulting current of 0.5 A. He used the formula R = VI and obtained an answer of 2 . Was Stu’s answer correct? How do you know?

Respuesta :

skyluke89

Answer: no, Stu's answer was incorrect.

Explanation:

The correct formula that relates current, resistance and voltage in a circuit is given by Ohm's law:

[tex]V=RI[/tex]

or

[tex]R=\frac{V}{I}[/tex]

where

V is the voltage in the circuit

I is the current

R is the resistance

In this circuit, the voltage is V=4.0 V, and the current is I=0.5 A, therefore the resistance of the circuit is

[tex]R=\frac{V}{I}=\frac{4.0 V}{0.5 A}=8 \Omega[/tex]

Lanuel

Applying Ohm's law, the resistance of the light bulb is 8 Ohms and Stu’s answer was incorrect.

Given the following data:

  • Voltage = 4.0 Volts
  • Current = 0.5 Amperes

To calculate the resistance of the light bulb, we would apply Ohm's law:

Ohm's law states that at constant temperature, the current flowing through an electrical circuit is directly proportional to the voltage applied across the two terminals of the circuit and it's inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

[tex]V = IR[/tex]

Where;

  • V is voltage measured in Volts.
  • I is current measured in Amperes.
  • R is resistance measured in Ohms.

Making resistance (R) the subject of formula:

[tex]R = \frac{V}{I}[/tex]  (Obviously, Stu was wrong with the formula he used)

Substituting the given parameters into the formula, we have;

[tex]R = \frac{4}{0.5}[/tex]

Resistance, R = 8 Ohms.

Therefore, the resistance of the light bulb is 8 Ohms.

Read more: https://brainly.com/question/23754122

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