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Highway engineers design a parabolic curve for an entrance ramp from a straight street to an interstate highway (see figure 64 on page 742 of your textbook). The vertex of the curve passes through (0, 0) and the parabola passes through (1000, + 800). Find an equation for the parabola.

Respuesta :

apologiabiology
if the vertex is (h,k)
then the equation of a parabola can be written as
y=a(x-h)^2+k

so since the vertex is (0,0)
y=a(x-0)^2+0
y=a(x)^2
y=ax^2
and the oint it passes through is 1000, 800 so
800=a(1000)^2
800=1000000a
divide both sides by 1000000
800/1000000=a
1/1250

the equatino is
[tex]y= \frac{1}{1280}x^2 [/tex]

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