Respuesta :
A) 47.3
First find out the volume of so3 using unitary method and the multiply it with the density of so3...
First find out the volume of so3 using unitary method and the multiply it with the density of so3...
Answer:
A) 47.3 g
Explanation:
2SO2(g) + O2(g) → 2SO3(g)
From the balanced equation above, we can tell that;
1 mol of oxygen molecule produces 2 mol of SO3 molecule.
At Standard Temperature and Pressure (STP), 1 mole of any gas will occupy a volume of 22.4 L.
This means 22.4 L of O2 produces 2 mol of SO3.
In order to calculate the mass of SO3 produced, we use the formular;
mass = Molar mass * Number of moles
Molar mass of SO3 = 32 + 16*3 = 32 + 48 = 80 g/mol
mass = 80 * 2 = 160g
This meas 22.4L produces 160g. How many g would 6.60 L produce?
22.4 = 160
6.60 = x
Upon cross multiplication,
x = (6.60 * 160) / 22.4
x = 47.14g
