Respuesta :
Answer : The mass of [tex]H_2[/tex] in grams is 0.102g.
Solution : Given,
Molar mass of [tex]NH_3[/tex] = 17.03 g/mole
Molar mass of [tex]H_2[/tex] = 2.0158 g/mole
Given Mass of [tex]NH_3[/tex] = 0.575 g
First we have to calculate the moles of [tex]NH_3[/tex].
[tex]\text{ Moles of }NH_3=\frac{\text{ Given mass of }NH_3}{\text{ Molar mass of }NH_3}[/tex] = [tex]\frac{0.575g}{17.03g/mole}[/tex] = 0.0337 moles
The given balanced equation is,
[tex]3H_2(g)+N_2(g)\rightarrow 2NH_3(g)[/tex]
From the above reaction, we conclude that
2 moles of [tex]NH_3[/tex] produced from 3 moles of [tex]H_2[/tex]
then the 0.0337 moles of [tex]NH_3[/tex] produces to give [tex]\frac{3moles\times 0.0337moles}{2moles}[/tex] moles of [tex]H_2[/tex]
The moles of [tex]H_2[/tex] = 0.0505 moles
The mass of [tex]H_2[/tex] = Moles of [tex]H_2[/tex] × Molar mass of [tex]H_2[/tex] = 0.0505 moles × 2.0158 g/mole = 0.10179 g
The mass of [tex]H_2[/tex] in the correct number of significant figures is 0.102 g.
