Probability of success is p =0.14
Probability of failure is q = 1 - p = 0.86
From probability theory, the probability of two consecutive successes is
p^2 = 0.0196.
In a Bernoulli trial (with n simulations) and r successes), the probability of success is
nCr*p^r*q^(n-r).
Try n=70, r=2
P(success) = 70C2*0.14^2*0.86^68 = 0.0017
Try n=80, r=2
P(success) = 80C2*0.14^2*0.86^78 = 0.0005
Try n=50, r=2
P(success) = 50C2*0.14^2*0.86^48 = 0.0172
Try n=60, r=2
P(success) = 60C2*0.14^2*0.86^58 = 0.0055
The closest answer to 0.0196 occurs when = 50
Answer: C. 50
