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If f(x)=square root x-3, which inequality can be used to find the domain of f(x)? A square root x-3 =>0 B x-3=>0 C square root x-3<=0 D x-3<=0

Respuesta :

madysonschneide
the answer is x-3=>0 i just took the quiz
calculista

we have

[tex]f(x)=\sqrt{x-3}[/tex]

we know that

The term in the root square can not be a negative number

so

[tex](x-3)\geq0\\x\geq3[/tex]

the domain is the interval----------> [3,∞)

therefore

the answer is the option

B (x-3)=>0

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