Answer:
The product of (4p – 6)(4p + 6) is ( 16p² - 36 )
Step-by-step explanation:
Let first number is, n₁ = ( 4p - 6 )
Second number is, n₂ = ( 4p + 6 )
We have to find the product of above two numbers. It can be calculated using algebraic identities as :
[tex](a-b)(a+b)=a^2-b^2[/tex]
In given question, a = 4p and b = 6
So, the product of above two numbers is :
[tex](4p-6)(4p+6)=(4p)^2-(6)^2=16p^2-36[/tex]
So, the product of (4p – 6)(4p + 6) is ( 16p² - 36 ). Hence, this is the required solution.
