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The launching velocity of a missile is 20.0 m/s, and it is shot at 53º above the horizontal. Which of the velocity components (neglecting air resistance) remains constant throughout the flight?

Respuesta :

AL2006
Neglecting air resistance, the horizontal component remains constant. The angle doesn't matter.

Answer:

Horizontal component of velocity will remains conserved which is v = 12 m/s

Explanation:

Two components of velocity of the projectile is given as

[tex]\vec v = 20 cos53 \hat i + 20 sin53 \hat j[/tex]

[tex]\vec v = 12\hat i + 16\hat j[/tex]

now we know that the acceleration is only due to gravity as we are considering the force is only vertically downwards due to gravity and there is no air resistance during whole motion.

So we will have acceleration as

[tex]\vec a = 0\hat i - g\hat j[/tex]

now we can say that here we do not have any acceleration along horizontal direction so this component of velocity will remain conserved.

So the constant component of velocity is along horizontal component and it is given by v = 12 m/s

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