Answer:
The equation of parabola with vertex at (-2,0)
y^2= 4a (x+2)
Step-by-step explanation:
Given the vertex of parabola at (-2,0).
We know that equation of parabola along x- axis when vertex at (h,k)
[tex](y-k)^2=4a(x+h)[/tex]
Given vertex (-2,0)
h= -2 and k=0
It means parabola along x- axis and passing through the point (-2,0).
The vertex of parabola is the highest or lowest point
Or
The vertex of parabola is the point of maximum or minimum.
The vertex is the point of where parabola intersect the axis.
We are given vertex (-2,0)
It means parabola intersect the x- axis at point (-2,0).
Put the value of vertex in the equation of parabola when its axis parallel to x- axis
Equation of parabola
[tex](y-k)^2=4a(x-h)[/tex]
Put h=-2 and k=0 in the equation of parabola
Then we get the equation of parabola
[tex]y^2=4a(x+2)[/tex]
Hence , the required equation of parabol [tex]y^2=4a(x+2)[/tex].
