We have that for the Question "A 12.39 g sample of phosphorus reacts with 42.54 g of chlorine to form only phosphorus trichloride (pcl3). if it is the only product" it can be said that
PCL_2=54.93 PCl_3
From the question we are told
A 12.39 g sample of phosphorus reacts with 42.54 g of chlorine to form only phosphorus trichloride (pcl3). if it is the only product, what mass of pcl3 is formed?
Generally the equation for the is mathematically given as
[tex]moles =\frac{givenmass}{mol.mass}[/tex]
Therefore
[tex]moles of P(n_1)=\frac{12.39}{30.9738}\\\\moles of P(n_1)=0.4mol\\\\moles of Cl_2=\frac{42.54}{70.904}\\\\moles of Cl_2=0.6\\\\[/tex]
Therefore
[tex]PCL_2 formed\\\\PCL_2=0.599945*2/3*(137.3334)[/tex]
PCL_2=54.93PCl_3
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