Respuesta :

[tex]3x^2-5x+ 7 = 0 \\ D=b^2-4ac=(-5)^2-4*3*7=25-84=-59 \\ D\ \textless \ 0 \ \ \to \ \ The \ equation \ has \ no \ roots[/tex]
3x²-5x+7=0

this equation doesn't have real roots.
So we have to apply the quadratic formula.
x= -b±√b²-4ac/2a
On putting the values, we will get our roots as
5+59i/6 and 5-59i/6


If you think it helped you, then please mark it as the brainliest answer.



P.S.- Sorry I didn't have PC. So no bold text.