We are given that ΔABC is isosceles with AB ≅ AC. Using the definition of congruent line segments, we know that . Let’s assume that angles B and C are not congruent. Then one angle measure must be greater than the other. If m∠B is greater than m∠C, then AC is greater than AB by the . However, this contradicts the given information that . Therefore, , which is what we wished to prove. Similarly, if m∠B is less than m∠C, we would reach the contradiction that AB > AC. Therefore, the angles must be congruent.

Respuesta :

An isosceles triangle is one with two equal sides and two equal angles. So that the following can be deduced from the given question:

A. AB ≅ AC (segment property of isosceles triangle).

B. By the triangle sides and angle theorem.

C. Side AB is congruent to side AC (i.e AB = AC).

D. m<B = m<C  (congruent angle property of isosceles triangles)

A triangle is said to be isosceles when it has two sides and angles to be equal. So that in the given question, it can be deduced that:

AB ≅ AC (segment property of isosceles triangle)

If the two base angles are not congruent, then it can be inferred that:

       AB [tex]\neq[/tex] AC

Also,

If m∠B is greater than m∠C (the base angles), then segment AC is greater than AB by the triangle sides and angles theorem. The theorem state that; the longer side of a triangle is always opposite to the greater angle.

Therefore, we can not prove that side AB is congruent to AC.

Only if we want to prove that AB = AC, then;

m<B = m<C  (congruent angle property of isosceles triangles)

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Answer:

1.   AB = AC

2.   Triangle parts relationship theorem

3.   Side AB is congruent to side AC

4.   Angle B is congruent to angle C

Step-by-step explanation:


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