Respuesta :
Explanation:
It is known that in an electrochemical cell, chemical reaction occurring at the electrodes generates a potential difference.
In an electrochemical cell, oxidation process occurs at anode and reduction process occurs at cathode.
For example, [tex]Ba^{+} + Ca^{2+} \rightarrow Ba^{2+} + Ca[/tex]
Cathode: [tex]Ca^{2+} + 2e^{-} \rightarrow Ca[/tex]
Anode : [tex]2Ba^{+} \rightarrow Ba^{2+} + 2e^{-}[/tex]
Also, it is known that when more negative is the value of [tex]E^{o}[/tex] more easily an atom can lose electrons. Hence, oxidation will occur where [tex]E^{o}[/tex] value is more negative.
Thus, calculate the overall cell potential as follows.
[tex]E^{o}[/tex] = [tex]E^{o}_{cathode}[/tex] - [tex]E^{o}_{anode}[/tex]
= [-2.87 - (-2.90)] V
= 0.03 V
Thus, we can conclude that overall cell potential for the given redox reaction is 0.03.
