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A quarterback throws a football to a teammate. The football is 6.5ft above the ground when it leaves the quarterback's hand. His teammate catches it 3.5s later, at a height above the ground of 5 ft.

Projectile motion formula

h(t) = -16t2 + vt + h0

h0 = 6.5

v = ?

h = 5 when t = 3.5

Respuesta :

Luv2Teach
You fill in the formula with the info they give you and solve for v:
5 = -16(3.5)^2 + 3.5v + 6.5  That simplifies to 5 = -196 + 3.5v + 6.5   Now simplify further by combining like terms and getting the v term by itself on one side. 194.5 = 3.5v   Now divide both sides by 3.5 to get a velocity of 55.57 feet per second.
fichoh

The value of velocity, V for the given projectile motion formular is 54.14 m/s

Using the projectile motion formula :

  • h(t) = - 16t² + vt + h0
  • h0 = 6.5 ; h = 5 ; t = 3.5

To obtain the value of v ; we input the given values into the motion equation :

h(3.5) = - 16(3.5²) + 3.5v + 6.5

h(3.5) = - 16(12.25) + 3.5v + 6.5

h(3.5) = - 196 + 3.5v + 6.5

Collect like terms

-3.5v = 6.5 - 196

-3.5v = - 189.5

Divide both sides by -3.5 to isolate v

v = (189.5 / 3.5)

v = 54.14

Therefore, the value of velocity, V for the given parameter values is 54.14

Learn more : https://brainly.com/question/2818076

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