Answer:
Step-by-step explanation:
1. The given equation is:
[tex]y-0.32y[/tex]
Upon solving, we get
[tex]y-0.32y=0.68y[/tex]
2. The given equation is:
[tex]y+0.32y[/tex]
Upon solving, we get
[tex]y+0.32y=1.32y[/tex]
3. The given equation is:
[tex]y+{\frac{2}{5}}y[/tex]
Upon solving, we get
[tex]y+{\frac{2}{5}}y=\frac{5y+2y}{5}={\frac{7}{5}}y[/tex]
4. The given equation is:
[tex]y-{\frac{2}{5}}y[/tex]
Upon solving, we get
[tex]y-{\frac{2}{5}}y=\frac{5y-2y}{5}={\frac{3}{5}}y[/tex]
Thus, pairs are:
[tex]{\frac{7}{5}}y---------->y+{\frac{2}{5}}y[/tex]
[tex]0.68y----------->y-0.32y[/tex]
[tex]{\frac{3}{5}}y----------->y-{\frac{2}{5}}y[/tex]
[tex]1.32y----------->y+0.32y[/tex]