Answer:
1.0 mol
Explanation:
Let's consider the synthesis of aluminum oxide.
2 Al + 1.5 O₂ → Al₂O₃
The molar mass of Al is 27 g/mol. The moles represented by 54 g of Al are:
54 g × (1 mol/ 27 g) = 2.0 mol
The molar ratio of Al to Al₂O₃ is 2:1. The moles of Al₂O₃ are:
2.0 mol Al × (1 mol Al₂O₃/2 mol Al) = 1.0 mol
1.0 mol of Al₂O₃ is formed.
1 mol of aluminum oxide will be formed from 54 g of aluminum since the molar ratio of [tex]\bold {Al }[/tex] and Aluminium oxide is 2:1.
What is the Mole concept?
A mole is a number of atoms, ions, or molecules as many as a number of atoms present in 12 g of Carbon 12.
The given chemical reaction is:
[tex]\bold {4Al + 3O_2 \rightarrow 2Al_2O_3}[/tex]
From the equation, the molar ratio of the [tex]\bold {Al }[/tex] and Aluminium oxide is 2:1. The molar mass of the Aluminium is 27 g/mol.
So,
[tex]n = \dfrac w m[/tex]
Where,
[tex]n[/tex] - number of moles
[tex]w[/tex] - mass = 54 g/mol
[tex]m[/tex] - molar mass = 27 g /mol
So,
[tex]n = \dfrac {54 }{27}\\\\n = 2 \rm \ mol[/tex]
Since the molar ratio of [tex]\bold {Al }[/tex] and Aluminium oxide is 2:1, 1 mol of aluminum oxide will be formed from 54 g of aluminum.
Learn more about the mole concept:
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