Respuesta :
1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythegorean theorem, as shown in the picture, the height is [tex] \frac{ \sqrt{3} }{2} a[/tex]
2. if a a=25 ft, then the height is [tex]\frac{ \sqrt{3} }{2} a=\frac{ \sqrt{3} }{2} *25= \frac{1.732}{2}*25= 21. 7[/tex] (ft)
3. consider picture 2. Let the length of the roof be l feet.
one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l
the lateral Area of the roof is 3a*l
the area of the equilateral surfaces is [tex]2*( \frac{1}{2} *a* \frac{ \sqrt{3} }{2}a )=\frac{ \sqrt{3} }{2} a^{2} [/tex]
so the total area of the roof is [tex]\frac{ \sqrt{3} }{2} a^{2} +3al[/tex]
4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.
So the total area found previously will be decreased by al
5. so the area now is [tex]\frac{ \sqrt{3} }{2} a^{2} +2al[/tex]
6. now a=25 and l=2a=50
Area=[tex]\frac{ \sqrt{3} }{2} a^{2} +2al=\frac{ \sqrt{3} }{2} * 25^{2}+2*25*50=25 ^{2} (\frac{ \sqrt{3} }{2} +4)=625*4.866[/tex]
=3041.3 (ft squared)
2. if a a=25 ft, then the height is [tex]\frac{ \sqrt{3} }{2} a=\frac{ \sqrt{3} }{2} *25= \frac{1.732}{2}*25= 21. 7[/tex] (ft)
3. consider picture 2. Let the length of the roof be l feet.
one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l
the lateral Area of the roof is 3a*l
the area of the equilateral surfaces is [tex]2*( \frac{1}{2} *a* \frac{ \sqrt{3} }{2}a )=\frac{ \sqrt{3} }{2} a^{2} [/tex]
so the total area of the roof is [tex]\frac{ \sqrt{3} }{2} a^{2} +3al[/tex]
4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.
So the total area found previously will be decreased by al
5. so the area now is [tex]\frac{ \sqrt{3} }{2} a^{2} +2al[/tex]
6. now a=25 and l=2a=50
Area=[tex]\frac{ \sqrt{3} }{2} a^{2} +2al=\frac{ \sqrt{3} }{2} * 25^{2}+2*25*50=25 ^{2} (\frac{ \sqrt{3} }{2} +4)=625*4.866[/tex]
=3041.3 (ft squared)


2. if a a=25 ft, then the height is (ft)
3. one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l the lateral Area of the roof is 3a*l
4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.
So the total area found previously will be decreased by al
5. so the area now is
6. now a=25 and l=2a=50
Area=
=3041.3 (ft squared)