P = 6,600
A = 6,000
t = 4
k = ?
6600 = 6000e^(4k)
6600/6000 = e^(4k)
1.1 = e^(4k)
Take the natural log of both sides.
ln 1.1 = 4k ln e (remember that ln e = 1)
ln 1.1 = 4k
(ln 1.1) / 4 = k
k = 0.0238
Bacteria after 10 hours.
P = 6000e^(0.0238*10)
= 6000e^0.238
= 7612
Therefore, the bacteria will grow to 7612 after 10 hours.
