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When 7.0 mol Al react with 8.5 mol HCl, what is the limiting reactant and how many moles of AlCl3 can be formed?

2 Al + 6 HCl yields 2 AlCl3 + 3 H2

Al is the limiting reactant; 7.0 mol AlCl3 can be formed
HCl is the limiting reactant; 2.8 mol AlCl3 can be formed
Al is the limiting reactant; 3.5 mol AlCl3 can be formed
HCl is the limiting reactant; 8.5 mol AlCl3 can be formed

Respuesta :

option 2 is Correct.
because, in the standard reaction, 2 moles of Al reacts with 6 of moles of HCl.
if 7 moles of Al are there, it will require 21 mole of HCl. So HCl Is the limiting reagent.

Now, 6 moles of HCl gives 2 moles of AlCl3, then 8.5 moles of HCl will give 2.84 moles of AlCl3.

B. HCl is the limiting reactant; 2.8 mol AlCl3 can be formed

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