Respuesta :

[tex]\frac{2}{3}(5 *4)/3+\frac{6}{7}\\\\\frac{2*5*4}{3}*\frac{1}{3}+\frac{6}{7}\\\\\frac{2*5*4}{3*3}+\frac{6}{7}\\\\\frac{40}{9}+\frac{6}{7}\\\\\frac{40}{9}*1+\frac{6}{7}*1\\\\\frac{40}{9}(\frac{7}{7})+\frac{6}{7}(\frac{9}{9})\\\\\frac{280}{63}+\frac{54}{63}\\\\\frac{334}{63}=5\ \frac{19}{63}[/tex]
FLORC
(pemdas)
this is the order you do the math
parenthesis
exponents
multiplication or division which ever is first
Addition or subtraction which ever is first

2/3 (5 x 4) ÷ 3 + 6/7
2/3 (20)÷3+6/7
40/3÷3+6/7
40/9+6/7
find common denominator
280/63+54/63
334/63 or 5.301