contestada

What is the equation in point-slope form of the line passing through (0, 5) and (−2, 11)? y − 5 = −3(x + 2) y − 5 = 3(x + 2) y − 11 = −3(x − 2) y − 11 = −3(x + 2)

Respuesta :

ghanami
hello : 

Hello : let  A(0,5)    B(-2,11)
the slope is :   (YB - YA)/(XB -XA)
(11-5)/(-2-0)  = 6/(-2)
the slope is : -3

the equation in point-slope form of the line is : y-11 = -3(x+2)
JeanaShupp

Answer: [tex]y-11=-3(x+2)[/tex]


Step-by-step explanation:

Given points :  (0, 5) and (−2, 11)

Slope of the line passing through given points .

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{11-5}{-2-0}=\frac{6}{-2}=-3[/tex]

Thus, slope of line passing through given points m=-3

We know that the equation of a line passing through points [tex](x_0,y_0)[/tex] with slope 'm' is [tex](y-y_0)=m(x-x_0)[/tex]

Thus, equation of a line passing through (−2, 11) with slope m=-3 will be

[tex](y-11)=(-3)(x-(-2))\\\Rightarrow\ y-11=-3(x+2)[/tex]

Hence, the equation of line is [tex]y-11=-3(x+2)[/tex]

Otras preguntas