For this question, Determine if the equation is always, sometimes, or never true. If the equation is sometimes true, determine the numbers that make it true.
The equation is: 6y + 5 = 4y + 5 and -2(6 - 10n) = 10(2n - 6)
If I've understood correctly, First eq'n: True only when y = 0 [simply rearrange the eq'n to solve for y] Second eq'n: Never true [when you expand and simplify you will get some two different integers equated to each other which is incorrect; the integers will vary depending on how and how much simplifying you do]
