Respuesta :
d=vt
1680=5(p-w)
p-w=336
1680=4(p+w)
p+w=420
p-w+p+w=336+420
2p=756
p=378 mph, and since w=420-p
w=42 mph
So the plane's velocity in still air is 378 mph and the wind speed is 42mph.
1680=5(p-w)
p-w=336
1680=4(p+w)
p+w=420
p-w+p+w=336+420
2p=756
p=378 mph, and since w=420-p
w=42 mph
So the plane's velocity in still air is 378 mph and the wind speed is 42mph.
Answer: The speed of wind is 378 mph.
The speed of airplane is 42 mph.
Step-by-step explanation:
Distance an airplane travels = 1680 miles
Against the wind in 5 miles,
Let the speed of wind be x
Let the speed of airplane be y.
So, for against the wind , it becomes,
[tex]\frac{1680}{5}=x-y\\\\336=x-y--------(1)[/tex]
similarly,
with the wind , it becomes,
[tex]\frac{1680}{4}=x+y\\\\420=x+y------(2)[/tex]
From Eq(1) and Eq(2), we get,
[tex]x-y=336\\x+y=420\\-----------------\\2x=756\\\\\implies x=\frac{756}{2}=378\ mph[/tex]
Hence, the speed of wind is 378 mph.
The speed of airplane is given by
[tex]y=420-378=42\ mph[/tex]