Respuesta :
Quadratic Formula:
-b +/- √b² - 4ac
x = --------------------------
2a
In your equation 3x² + 5x + 2 = 0:
a = 3
b = 5
c = 2
Now, plug in these values into the formula.
-5 +/- √5² - 4(3)(2) -5 +/- √25 - 4(6)
x = -------------------------------- ⇒ x = -----------------------------
2(3) 6
-5 +/- √25 -24 -5 +/- √1 -5 +/- 1
x = ------------------------ ⇒ x = --------------- ⇒ x = --------------
6 6 6
-5 +/- 1
Split x = ------------ into two solutions by solving it.
6
-5 + 1 -4
x = ------------ = ------
6 6
-5 - 1 -6
x = ----------- = ------ = -1
6 6
The two final solutions are x = -1 and x = -4/6
-b +/- √b² - 4ac
x = --------------------------
2a
In your equation 3x² + 5x + 2 = 0:
a = 3
b = 5
c = 2
Now, plug in these values into the formula.
-5 +/- √5² - 4(3)(2) -5 +/- √25 - 4(6)
x = -------------------------------- ⇒ x = -----------------------------
2(3) 6
-5 +/- √25 -24 -5 +/- √1 -5 +/- 1
x = ------------------------ ⇒ x = --------------- ⇒ x = --------------
6 6 6
-5 +/- 1
Split x = ------------ into two solutions by solving it.
6
-5 + 1 -4
x = ------------ = ------
6 6
-5 - 1 -6
x = ----------- = ------ = -1
6 6
The two final solutions are x = -1 and x = -4/6
