Answer:
0.3125%
Step-by-step explanation:
P(E)=Number of favourable outcomes/Total number of possible outcomes
Total number of possible outcomes=16 {HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TITH, TITT}
Number of favourable outcomes=5{HHHH, HHHT, HHTH, HTHH, THHH}
P(E)=5/16=0.3125%
Hope this helps!
Answer:
C) 31.25%
Step-by-step explanation:
Theoretical probability is the likelihood of an event occurring based on mathematical reasoning or analysis of all possible outcomes in a well-defined and equally likely sample space.
To determine the probability of getting at least 3 heads when tossing a coin 4 times, we need to identify the outcomes in the sample space that meet this condition and calculate the probability.
There are 5 outcomes with at least 3 heads are:
There are a total of 16 outcomes in the sample space. Therefore, the probability of getting at least 3 heads is given by the ratio of the favorable outcomes to the total outcomes:
[tex]\sf P(\textsf{at least 3 heads}) = \dfrac{\textsf{Number of favorable outcomes}}{\textsf{Total number of outcomes}}[/tex]
[tex]\sf P(\textsf{at least 3 heads}) = \dfrac{5}{16}[/tex]
[tex]\sf P(\textsf{at least 3 heads}) = 0.3125[/tex]
[tex]\sf P(\textsf{at least 3 heads}) = 31.25\%[/tex]
Therefore, probability of getting at least 3 heads when tossing a coin 4 times is:
[tex]\Large\boxed{\boxed{\sf31.25\%}}[/tex]
