Answer:
(0,4) is the y-intercept
(-2,0) is the x intercept
Step-by-step explanation:
I'll assume "f(x)=x2+4x+4" is supposed to be f(x)=x^2+4x+4.
See the attached graph. The x and y intercepts are the values of x and y when one of the two is equal to zero:
(0,y) is the y-intercept
(x,0) is the x intercept
For the equation f(x)=x^2+4x+4:
(0,4) is the y-intercept
(-2,0) is the x intercept
One can also find these values by solving the equation:
y-intercept:
y = x^2 + 4x + 4
What is the value of y when x = 0?
y = 0^2 + 4*0 + 4
y = 4
y-intercept is (0,4)
X-intercept:
y = x^2 + 4x + 4
What is the value of x when y = 0?
0 = x^2 + 4x + 4
0 = (x + 2)*(x+2)
x = -2
x-intercept is (-2,0)
