let us determine the pressure of water at each of three states
defined by a temperature of 100°C and specific volumes, respectively, of y1 5
2.434 m 3
/kg, y2 5 1.0 m 3
/kg, and y 3 5 1.0423 3 10 −3 m 3
/kg. Using the known
temperature, Table A-2 provides the values of yf and yg : yf 5 1.0435 3 10−3 m 3
/kg,
yg 5 1.673 m 3
/kg. Since y1 is greater than yg , state 1 is in the vapor region. Table
A-4 gives the pressure as 0.70 bar. Next, since y2 falls between yf and yg , the
pressure is the saturation pressure corresponding to 100°C, which is 1.014 bar.
Finally, since y3 is less than yf , state 3 is in the liquid region. Table A-5 gives the
pressure as 25 bar