Answer:
74658
Step-by-step explanation:
I will mark the digits by A,B,C,D and E by the order of the number
E+C=14
B+1=D
2B-1=A
B+C=10
A+B+C+D+E=30
I will isolate every variable to make it equal to an equation with the variable D
B=D-1
2(D-1)-1=A
2D-2-1=A
2D-3=A
B=D-1
10-C+1=D
-C+11=D
11-D=C
D=D
E+11-D=14
E-D=3
E=D+3
Now we can fill this into the big equation that equals 30 to find D
(2D-3)+(D-1)+(11-D)+(D)+(D+3)=30
(3D-4)+(11)+(D+3)=30
4D+10=30
4D=20
D=5
Now we know the fourth digit is 5
We can easily find B now using the second equation
B+1=5
B=4
Now we know the second digit is 4
We can find A by filling in the third equation
2(4)-1=A
8-1=A
7=A
We can find C by filling in the fourth equation
4+C=10
C=6
Now we can find E using the first equation
E+6=14
E=8
So the code in order should be 74658
I hope this helps, im sorry this is sloppy is was experiment to see what worked, please let me know if you have any questions on any of this