Respuesta :
Answer:
Step-by-step explanation:
Let's denote the width of the rectangle as \( W \) and the length as \( L \).
The given information can be translated into two equations:
1. Perimeter of a rectangle: \( 2L + 2W = 20 \)
2. Length is 6 units longer than the width: \( L = W + 6 \)
Now, we can solve for the dimensions of the rectangle using these equations. Here are three different ways to do it:
### Method 1: Substitution
Start with the equation \( L = W + 6 \) and substitute it into the perimeter equation:
\[ 2(W + 6) + 2W = 20 \]
Solve for \( W \) and then find \( L \) using \( L = W + 6 \).
### Method 2: Elimination
Combine the two equations to eliminate \( L \) and solve for \( W \):
\[ 2(W + 6) + 2W = 20 \]
Solve for \( W \) and then find \( L \) using \( L = W + 6 \).
### Method 3: Graphical
Graph the equations \( 2L + 2W = 20 \) and \( L = W + 6 \) on a coordinate plane. The point of intersection will give you the values of \( L \) and \( W \).
Choose the method that you find most convenient or are currently learning in your class. If you'd like a specific solution using one of these methods, let me know, and I can provide detailed steps.
