Answer:
the work done by the force generated by the propulsion unit is 1700 kg * m^2/s^2.
Explanation:
To find the work done by the force generated by the propulsion unit, we can use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy.
Given:
Initial speed (u) = 0 m/s (starting from rest)
Final speed (v) = 5.0 m/s
Height (h) = 16 m
Mass (m) = 136 kg
First, let's find the change in kinetic energy:
Change in kinetic energy (ΔKE) = (1/2) * m * (v^2 - u^2)
Substituting the values:
ΔKE = (1/2) * 136 kg * (5.0 m/s)^2 - 0 m/s)^2)
ΔKE = (1/2) * 136 kg * (25 m^2/s^2 - 0 m^2/s^2)
ΔKE = (1/2) * 136 kg * 25 m^2/s^2
ΔKE = 1700 kg * m^2/s^2
Now, since work (W) is equal to the change in kinetic energy, we have:
Work done by the force generated by the propulsion unit (W) = ΔKE
W = 1700 kg * m^2/s^2
Therefore, the work done by the force generated by the propulsion unit is 1700 kg * m^2/s^2.
