Answer:
16 cm
Step-by-step explanation:
Given:
- Length of the square ([tex]L[/tex]) is 20 cm.
- Length of the rectangle ([tex]l[/tex]) is 24 cm.
The equality of perimeters for the square and rectangle is expressed as:
Perimeter of square = Perimeter of rectangle
[tex] 4 \times L = 2 \times (l + b) [/tex]
Substitute the given values:
[tex] 4 \times 20 = 2 \times (24 + b) [/tex]
Simplify:
[tex] 80 = 48 + 2b [/tex]
Isolate [tex]b[/tex]:
[tex] 2b = 80 - 48 [/tex]
[tex] 2b = 32 [/tex]
[tex] b =\dfrac{32}{2}[/tex]
[tex] b = 16 [/tex]
Therefore, the breadth of the rectangle ([tex]b[/tex]) is 16 cm.
