An egg is dropped from the top of
a building. After falling for 3.17 s,
how far has it fallen?
Ay = [?] m
Remember: falling = -v
lost height = -Ay
g= -9.80 m/s²

Respuesta :

Answer:

Explanation

To calculate the distance an object has fallen after a given time due to gravity, we can use the formula:

d = 0.5 * g * t^2 [[2]](https://www.physicsclassroom.com/class/1DKin/Lesson-5/How-Fast-and-How-Far)

where d is the distance fallen, g is the acceleration due to gravity (-9.8 m/s²), and t is the time in seconds.

Given that the egg has fallen for 3.17 seconds, we can substitute these values into the formula to find the distance fallen:

d = 0.5 * (-9.8 m/s²) * (3.17 s)^2

Calculating this, we find:

d ≈ 0.5 * (-9.8 m/s²) * (10.0489 s²) ≈ -49.01 m

Since the distance fallen cannot be negative, we take the absolute value of the result:

Ay ≈ 49.01 m

Therefore, after falling for 3.17 seconds, the egg has fallen approximately 49.01 meters