Respuesta :
Answer:
The mean speed of both Cu 2+ and SO 4 2− ions in the copper sulphate solution is 7.8 x 10^-9 m/s to 2 significant figures.
Explanation:
In the given experiment, a current of 3.5A is being passed through a copper sulphate solution in a 10cm cubical container, with the electrical terminals being opposite faces. This contains equal numbers of Cu 2+ and SO 4 2− ions which have respectively +2 and −2 electron charge units. Assuming that the two ions have equal speed in the solution, and that there are 6.0×10^26 of each per cubic metre of the solution, we can calculate their mean speed using the following formula:
mean speed = current / (charge x concentration x volume)
Here, the charge is the electron charge unit, which is 1.6 x 10^-19 C. The concentration of each ion is 6.0 x 10^26 ions/m^3, and the volume of the container is 0.1 m^3. Substituting these values into the formula, we get:
mean speed = 3.5 / (2 x 1.6 x 10^-19 x 6.0 x 10^26 x 0.1)
mean speed = 7.8 x 10^-9 m/s
Therefore, the mean speed of both Cu 2+ and SO 4 2− ions in the copper sulphate solution is 7.8 x 10^-9 m/s to 2 significant figures.
hope this helps!
