Bo is flying a kite , holding his hands a distance of 3.5 feet above the ground and letting all the kites string play out. He measures the angle of elevation from his hands to the kite to be 29 degree. If the string from the kite to his hand is 110 feet long, how many feet is the kite above the ground? round your answer to the nearest tenth foot if necessary

Respuesta :

Answer:

Step-In this scenario, Bo is forming a right triangle with the ground, where one leg is the distance from his hands to the ground (3.5 feet), the other leg is the height of the kite above the ground (the unknown we're trying to find), and the hypotenuse is the length of the kite string (110 feet).

The trigonometric relationship that relates the angle of elevation (θ), the opposite side (height of the kite above the ground), and the hypotenuse is given by the tangent function:

tan

(

)

=

Opposite

Adjacent

tan(θ)=

Adjacent

Opposite

In this case, the angle of elevation (θ) is 29 degrees, the opposite side is the height of the kite above the ground, and the adjacent side is the distance from Bo's hands to the ground. So, we have:

tan

(

2

9

)

=

height of kite

3.5

feet

tan(29

)=

3.5feet

height of kite

Solving for the height of the kite:

height of kite

=

3.5

feet

×

tan

(

2

9

)

height of kite=3.5feet×tan(29

)

height of kite

3.5

feet

×

0.5543

height of kite≈3.5feet×0.5543

height of kite

1.94105

feet

height of kite≈1.94105feet

Rounding to the nearest tenth foot, the height of the kite above the ground is approximately

1.9

1.9 feet.

by-step explanation: