The dimensions (length and width) of the rectangle are 20 and 10 centimeters respectively.
- Let the length of the rectangle be L.
- Let the width of the rectangle be W.
Given the following data:
-
Perimeter of rectangle = 60 centimeters
Translating the word problem into an algebraic equation, we have;
[tex]L = 2W[/tex]
To find the dimensions (length and width) of the rectangle;
Mathematically, the perimeter of a rectangle is given by the formula;
[tex]P = 2(L + W)[/tex]
Substituting the values into the formula, we have;
[tex]60 = 2(2W + W)\\\\60 = 2(3W)\\\\60 = 6W\\\\W = \frac{60}{6}[/tex]
Width, W = 10 centimeters
Next, we would find the value of L;
[tex]L = 2W[/tex]
Substituting the value of W, we have;
[tex]L = 2(10)[/tex]
Length = 20 centimeters
Therefore, dimensions (length and width) of the rectangle are 20 and 10 centimeters respectively.
Find more information: brainly.com/question/897975
