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Solve for the zeros of the quadratic function f(x) = x + 5 – 2x2. 1. Put the quadratic function in standard form. f(x) = –2x2 + x + 5 2. Set the function equal to 0 to create a quadratic equation. –2x2 + x + 5 = 0 3. Determine the values for a, b, and c. a = b = c = 4. Analyze the discriminant. b2 – 4ac = The quadratic function will have .

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Answer:

Step-by-step explanation:

Put the quadratic function in standard form.

[tex]f(x) = -2x^2 + x + 5[/tex]

2. Set the function equal to 0 to create a quadratic equation

[tex]-2x^2 + x + 5=0[/tex]

3. Determine the values for a, b, and c. a =2: b = -1:c = 5

4. Analyze the discriminant. [tex]b^2 – 4ac=1+4(2)(5)=41[/tex]

The quadratic function will have irrational real roots.

This is because discriminant is positive but not a perfect square

adioabiola

The quadratic function will have zeroes; x1 = (-1 + √41)/-4 and x2 = (-1 - √41)/-4

Zeros of quadratic functions

  • f(x) = -2x² + x +5

  • Rewritten as; -2x² + x +5 = 0

By comparison with the standard form of quadratic equations; ax² + bx + c = 0

Hence, a = -2, b = 1 and c = 5.

The discriminant given by; b² - 4ac is;

  • Discriminant, D = 1² - 4(-2×5)

  • D = 41

Hence the zeros mof.the function are;

  • x1 = (-1 + √41)/-4 and x2 = (-1 - √41)/-4

Read more on zeros of quadratic functions;

https://brainly.com/question/9761906

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